#118 Thermal Stress on Hot Runner Manifold (Practice Calculations)
Question,
Calculate the thermal stress σ acting on the manifold in the following example of settings.
However, your calculations should be based on the assumptions given below.
Overall length of the manifold L = 150 mm
Room temperature of a molding factory in Japan in December = 18°C
Plastic used = ABS plastic
Manifold steel material = S55C
Sample Answer
Firstly, we obtain the change in the dimensions Δl due to temperature rise as follows.
Δl = α ∙ Δt ∙ L |
Where,
α (alpha): Linear thermal expansion coefficient of the manifold steel material (mm/°C)
In the case of S55C, we assume that α is equal to 12×10-6 (mm/°C)).
Δt: Temperature change from room temperature up to the set temperature of the manifold (°C)
∴Δl = α ∙ Δt ∙ L |
= 12×10-6 × (230 - 18) × 150 |
= 0.3816 (mm). |
Therefore, the thermal stress σ is given by:
σ = ε ∙ E |
= Δl ∙ E/L |
Where,
ε (epsilon): strain (%), and
E: Young's modulus of the manifold steel material (MPa or kgf/mm2).
In the case of S55C, E = 21,000 kgf/mm2.
Δl (delta) = Amount of thermal expansion of length (mm)
L: Overall length of the manifold (mm)
∴σ = ε ∙ E |
= Δl ∙ E/L |
= 0.3816 × 21,000 / 150 |
= 53.424 (kgf/mm2) |
= 5342.4 (kgf/cm2) |



